If the coil has 20,855 turns and each turn is 1.75 inches long, how many feet of #24 AWG wire are required to wind the coil?

• A. 3,002 feet
• B. 3,042 feet
• C. 3,086 feet
• D. 3,012 feet

Answer: (B)

Multiply the number of turns by the length of wire per turn to get total length, then convert to feet. So you have 20,855 turns × 1.75 inches per turn = 36,496.25 inches of wire. Convert inches to feet by dividing by 12: 36,496.25 ÷ 12 ≈ 3,041.35 feet. That’s about 3,041 feet, and the closest listed option is 3,042 feet, which is why that choice matches.