A total load of 25,620 W is distributed over five circuits. If the load is instead distributed evenly over six circuits, what is the new average per circuit?

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Multiple Choice

A total load of 25,620 W is distributed over five circuits. If the load is instead distributed evenly over six circuits, what is the new average per circuit?

Explanation:
Distributing the same total load across more circuits lowers the average per circuit because you’re spreading the same power over more paths. Divide the total by the new number of circuits: 25,620 W ÷ 6 = 4,270 W per circuit. Check: 4,270 × 6 = 25,620, so the numbers align. The new average per circuit is 4,270 W.

Distributing the same total load across more circuits lowers the average per circuit because you’re spreading the same power over more paths. Divide the total by the new number of circuits: 25,620 W ÷ 6 = 4,270 W per circuit. Check: 4,270 × 6 = 25,620, so the numbers align. The new average per circuit is 4,270 W.

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